sebasm4567 sebasm4567
  • 06-06-2023
  • Mathematics
contestada

f(t)={ 0
t
​
(−π≤t<0)
(0≤t<π)
​
(2) f(t)=π−∣t∣(−π≤t<π) （ヒント: f(t) は偶関数なので積分区間は (0≤t<π) を考えればよい)

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