lovebug9084 lovebug9084
  • 09-01-2024
  • Mathematics
contestada

Two free charges q and 4q are placed at a distance d apart. A third charge Q is placed between them at a distance x from charges q such that the system is in equilibrium.Then
A. Q=4q/9
B. Q=7q/9
C. Q=−3q/9³
D. Q=−2q/9

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