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06-03-2024
Chemistry

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What is for the equation below? naoh(aq) hcl(aq) right arrow. h₂o(l) nacl(aq) = -56.13 kj = 87.1 j/k t = 303 k use delta.g = delta.h tdelta.s. 82.5 kj 29.7 kj 26,500 kj 27,000 kj

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