tishacsimmons5648 tishacsimmons5648
  • 06-04-2024
  • Mathematics
contestada

The eccentric angles of the ends of latusrectum of the ellipse x²/a²+y²/b²=1 is:
A.sin⁻¹(±b/ae)
B.sec⁻¹(±b/ae)
C.cos⁻¹(±b/ae)
D.tan⁻¹(±b/ae)

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