In the following, assume all matrices involved (and their combinations) are square and invertible. Solve for X in terms of the other matrices and/or their inverses.

XA+B=XOA

a) X=−BA⁻¹OB
b) X=B(A⁻¹−I)B⁻¹
c) X=B(I−A)⁻¹
d) X=(I−A)⁻¹B
e) X=−A−1B
f) X=(A−I)⁻¹B