First we can find the number of moles of gas for the given volume at STP and then calculate the new volume Molar volume states that there 1 mol of any gas occupies a volume of 22.4 L at STP. Therefore if 22.4 L contains - 1 mol of gas then 25.0 L contains - 25.0 L / 22.4 L/mol = 1.12 mol when the pressure and temperature conditions are changed the number of moles of gas remains the same using the ideal gas law equation we can find the volume of the gas PV = nRT where P - pressure - 605 torr x 133.3 Pa/torr = 80 647 Pa V - volume n - number of moles - 1.12 mol R - universal gas constant - 8.314 Jmol⁻¹K⁻¹ T - temperature in kelvin - 55°C + 273 = 328 K substituting these values in the equation 80 647 Pa x V = 1.12 mol x 8.314 Jmol⁻¹K⁻¹ x 328 K V = 37.9 L new volume at the given conditions is 37.9 L