A cran uses an average force of 5200N to lift a steel beam 25m. How much work does the crane do on the steal beam.
Please help or explain how to do this anyone. Please and thank youu
The work done by a force is given by: [tex]W=Fd \cos \theta[/tex] where F is the magnitude of the force d is the distance covered by the object [tex]\theta[/tex] is the angle between the direction of the force and the direction of motion
In our problem, [tex]F=5200 N[/tex], [tex]d=25 m[/tex] and [tex]\theta=0[/tex] (because the force is parallel to the direction of motion), so the work done by the crane is [tex]W=(5200 N)(25 m)(\cos 0^{\circ})=1.3 \cdot 10^5 J[/tex]
