a) The ordered pair with -6 as the dependent value is (2, -6). g^-1(-6) = 2
b) Swap x and y and solve for y. x = 3y -4 x +4 = 3y (x +4)/3 = y Then the inverse function can be written as h^-1(x) = (x +4)/3
c) You have shown the product of h^-1(x) and h(x). We have to assume that is what you intend. h^-1(3) = (3 +4)/3 = 7/3 h(3) = 3×3 -4 = 5 (h^-1·h)(3) = h^-1(3)·h(3) = (7/3)·5 (h^-1·h)(3) = 35/3
