Isabelcastillox3420 Isabelcastillox3420
  • 10-05-2018
  • Mathematics
contestada

A rectangular room has an area of 315 square feet. the length is 6 feet more than the width. find the dimensions of the room.

Respuesta :

mkryukova19 mkryukova19
  • 14-05-2018
Width - x ft.
Length - (x+6)ft.

x(x+6)=315
x²+6x-315=0
a=1, b=6, c=-315

D=b²-4ac=36+4*1*315=1296, √D=√1296=36

[tex] x = \frac{-b+/- \sqrt{D} }{2a} \\ \\ x= \frac{-6+/-36}{2} \\ \\ x=15, x=-21[/tex]

For the width we can use only positive number. 
The width =15 ft.
The length =15+6=21 ft.

Check :
Area =15*21=315 ft²
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