Respuesta :

kamizam38
60/360*pi*6^2=6pi. (Area of a sector)

1/2*6*6*sin(60)=9root3. (Area of a triangle)

So it must be the top one


akwow0924
The first answer choice 6[tex] \pi [/tex] - 9[tex] \sqrt{3un} [/tex]²

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