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choixongdong
#17)

64^(x+3) * 64^(3x - 2) = (1/4)^(-2x - 2)
64^(x + 3 + 3x - 2) = (4^-1)^(-2x - 2)
64^(4x+1) = 4^(2x + 2)
(4^3)^(4x+1) = 4^(2x + 2)
4^(12x + 3) = 4^(2x + 2)

So 
12x + 3 = 2x + 2
10x = -1
    x = -1/10
    x = - 0.1

Hope it helps
mathstudent55
[tex] 64^{x + 3} \times 64^{3x - 2} = (\dfrac{1}{4})^{-2x + 2} [/tex]

[tex] 64^{x + 3 + 3x - 2} = (64^{-\frac{1}{3}})^{-2x + 2} [/tex]

[tex] 64^{4x + 1} = 64^{\frac{2}{3}x - \frac{2}{3}} [/tex]

[tex] 64^{4x + 1} = 64^{\frac{2x - 2}{3}} [/tex]

[tex] 4x + 1 = \dfrac{2x - 2}{3} [/tex]

[tex] 12x + 3 = 2x - 2 [/tex]

[tex] 10x = -5 [/tex]

[tex] x = -\dfrac{5}{10} [/tex]

[tex] x = -\dfrac{1}{2} [/tex]

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