08-06-2018
Mathematics

contestada

Find a cubic function with the given zeros. 3, -4, 7

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jdoe0001 jdoe0001

08-06-2018

[tex]\bf \begin{cases} x=3\implies &x-3=0\\ x=-4\implies &x+4=0\\ x=7\implies &x-7=0 \end{cases} \\\\\\ (x-3)(x+4)(x-7)=\stackrel{y}{0}\implies \stackrel{FOIL}{(x^2+x-12)}(x-7)=y \\\\\\ x^3+x^2-12x-7x^2-7x+84=y\implies x^3-6x^2-19x+84=y[/tex]

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