CSX
CSX
09-03-2016
Mathematics
contestada
!!!!!!!!!!!!150 points!!!!!!!!!! Question bellow.
Respuesta :
707863128
707863128
09-03-2016
The answer will be .04[tex] x^{2} [/tex] -0.2xy+0.25[tex] y^{2} [/tex]
using the formula [tex] a^{2} -2ab + b^{2} [/tex]
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apologiabiology
apologiabiology
09-03-2016
I thnk you means exand
so
(0.2x-0.5y)^2=(0.2x-0.5y)(0.2x-0.5y)
use distributive prpoety
a(b+c)=ab+ac
so
(0.2x-0.5y)(0.2x-0.5y)=(0.2x-0.5y)(0.2x)+(0.2x-0.5y)(-0.5y)=(0.2x)(0.2x)+(-0.5y)(0.2x)+(0.2x)(-0.5y)+(-0.5y)(-0.5y)=0.4x^2-0.2xy+0.25y^2
Answer Link
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