Equating the lengths, we have: [tex] 4x+y+2=3x+3y\Rightarrow x-2y=-2 [/tex]
Equating the widths, we have: [tex] 2x+y+1=12\Rightarrow2x+y=11 [/tex]
Solving the two equations simultaneously gives that x = 4 and y = 3.
Thus, the length is 4(4) + 3 + 2 = 21 and the width is 12.
Therefore area = length times width = 21 x 12 = 252 square units
perimeter = 2(length + width) = 2(21 + 12) = 2(33) = 66.
