[tex]y=\dfrac{1}{2}x-1\\\\for\ x=0\to y=\dfrac{1}{2}(0)-1=-1\to(0,\ -1)\\\\for\ x=2\to y=\dfrac{1}{2}(2)-1=0\to(2,\ 0)[/tex]
[tex]2y=x-2\ \ \ \ |:2\\\\y=\dfrac{1}{2}x-1!!![/tex]
[tex]\text{Both equations are identical. The solution is:}\\\\\left\{\begin{array}{ccc}x\in\mathbb{R}\\y=\dfrac{1}{2}x-1\end{array}\right [/tex]
