Answer: -
83.3 g of water can be vaporized by the addition of 45 kcal of heat at 100° C
Explanation: -
Heat of vaporization = 540 Cal / g.
Heat supplied = Q = 45 Kcal = 45 x 1000 Cal
Mass of water= Heat supplied / Heat of vaporization
= 45 x 1000 Cal / (540 Cal /g)
= 83.3 g
