vandarughb9314 vandarughb9314
  • 08-08-2018
  • Mathematics
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What is the orthocenter of a triangle with vertices A(−3,−2)A(−3,−2), B(−2,2)B(−2,2), and C(2,−2)C(2,−2)?

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DeanR
DeanR DeanR
  • 08-08-2018

A(−3,−2), B(−2,2), C(2,−2)

The orthocenter is the meet of the altitudes. We see AC is parallel to the x axis so the perpendicular [tex]x=-2[/tex] is the altitude through B.

Between A and B we have slope (2 - -2)/(-2 - -3) = 4 so perpendicular slope -1/4 through C(2,-2):

[tex]y+2 = -\frac 1 4 (x - 2)[/tex]

For the y coordinate of the orthocenter we substitute in x=-2.

[tex]y+2 = -\frac 1 4(-2 - 2) = 1[/tex]

[tex]y = -1[/tex]

So the orthocenter is (x,y)=(-2,-1)

Answer: (-2,-1)

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