saniya22 saniya22
  • 09-08-2018
  • Mathematics
contestada

What is the area of a rectangle with length 4x-3 and width 6x+9

Respuesta :

rejkjavik rejkjavik
  • 09-08-2018

We are given

length of rectangle is 4x-3

width of rectangle is 6x+9

we know that

Area of rectangle = length of rectangle*width of rectangle

so, we can plug value

and we get

[tex] Area=(4x-3)*(6x+9) [/tex]

now, we can distribute it

[tex] Area=4x*6x+4x*9-3*6x-3*9 [/tex]

now, we can simplify it

[tex] Area=24x^2+36x-18x-27 [/tex]

[tex] Area=24x^2+18x-27 [/tex]...............Answer

Answer Link
vunderkid
vunderkid vunderkid
  • 09-08-2018

Area of the rectangle is 24x²+18x-27

Answer Link

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