[tex] 16+0.81=16.81 [/tex]
Since the number system we use is base ten, that means we can write each number as a sum of a number times ten to some power. In this problem we actually have:[tex] 10^1+6*10^0+10^{-1}*8+10^{-2}*1=10+6+.8+.01=16.81 [/tex]
