Let the event [tex] A=\{ Horse \}, B=\{ Female \} [/tex]
The the probability of the events
[tex] P(A \cap B)=\frac{2}{14+26} =\frac{1}{20} [/tex]
[tex] P( B)=\frac{26}{14+26} =\frac{13}{20} [/tex]
The conditional probability
[tex] P(Horse|Female)=P(A|B)=\frac{P(A \cap B)}{P(B)} =\frac{1/20}{13/20}
=\frac{1}{13} [/tex]
