Respuesta :

choixongdong

Given f(x) = x^2 − 4x + 3 and g(x) = −x − 6

g(-2) = −(-2) − 6 = -4

f(g(−2)) = (-4)^2 − 4(-4) + 3

f(g(−2)) = 16 + 16 + 3

f(g(−2)) = 35

Answer

35

konrad509

[tex] f(g(x))=(-x-6)^2-4(-x-6)+3\\f(g(x))=x^2+12x+36+4x+24+3\\f(g(x))=x^2+16x+63\\\\f(g(-2))=(-2)^2+16\cdot(-2)+63=4-32+63=35 [/tex]