we are given equation as
[tex]u(x,y)=(x+2)(y+1)[/tex]
clara's indifference curve that goes through the point (x,y)=(2,8)
we can plug x=2 , y=8
[tex]u(x,y)=(2+2)(8+1)[/tex]
[tex]u(2,8)=36[/tex]
now, we can set it equal
we get
[tex]36=(x+2)(y+1)[/tex]
now, we can solve for y
[tex]\frac{\left(x+2\right)\left(y+1\right)}{x+2}=\frac{36}{x+2}[/tex]
[tex]y+1=\frac{36}{x+2}[/tex]
[tex]y=\frac{36}{x+2}-1[/tex]..........Answer
