Answer:
Atoms of Cr in 0.86 mol of K2CrO4 = 0.86 × 6.02*10^23 = 5.177 * 10^23 atoms.
Explanation:
- One mol of K2CrO4 contains 6.02*10^23 molecules of K2CrO4.
- One K2CrO4 contains 1 atom of Cr.
- So 0.86 mol of K2CrO4 contain 0.86 * 6.02*10^23.
- Which is equal to 5.177 * 10^23 atoms.
