Respuesta :

[tex]\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{2}{ h},\stackrel{1}{ k})\qquad \qquad radius=\stackrel{3}{ r} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ (x-2)^2+(y-1)^2=3^2\implies (x-2)^2+(y-1)^2=9[/tex]

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