Answer:
5i[tex]\sqrt{6}[/tex]
Step-by-step explanation:
using the rule of radicals
• [tex]\sqrt{a}[/tex] × [tex]\sqrt{b}[/tex] ⇔ [tex]\sqrt{ab}[/tex]
• [tex]\sqrt{-1}[/tex] = i
[tex]\sqrt{-150}[/tex]
= [tex]\sqrt{25}[/tex] × [tex]\sqrt{6}[/tex] × [tex]\sqrt{-1}[/tex]
= 5i[tex]\sqrt{6}[/tex]
