Answer: -12 < x < [tex]-\frac{9}{2}[/tex]
Step-by-step explanation:
2x + 9 < 0 and x > -12
2x < -9
x < [tex]-\frac{9}{2}[/tex]
Since it is an "and" statement, x is between -12 and [tex]-\frac{9}{2}[/tex], so -12 < x < [tex]-\frac{9}{2}[/tex]
Graph: -12 o-----------------o [tex]-\frac{9}{2}[/tex]
Interval Notation: (-12, [tex]-\frac{9}{2}[/tex])
