Answer:
yes
Step-by-step explanation:
As an example
(x₁, y₁ ) = (1,2) and (x₂, y₂ ) = (5,3), then
d = [tex]\sqrt{(5-1)^2+(3-2)^2}[/tex] = [tex]\sqrt{4^2+1^2}[/tex] = [tex]\sqrt{16+1}[/tex] = [tex]\sqrt{17}[/tex]
Now let (x₁, y₁ ) = (5,3) and (x₂, y₂ ) = (1,2), then
d = [tex]\sqrt{(1-5)^2+(2-3)^2}[/tex] = [tex]\sqrt{(-4)^2+(-1)^2}[/tex] = [tex]\sqrt{16+1}[/tex] = [tex]\sqrt{17}[/tex]
