djjfsdiofjs djjfsdiofjs
  • 07-01-2019
  • Mathematics
contestada

i need help please and thank u,

i need help please and thank u class=

Respuesta :

offguard
offguard offguard
  • 07-01-2019

The illegal values of b are when the denominator equals 0.

So, [tex]b^2-2b-8=0[/tex] gives you (b-4)(b+2)=0

Therefore, b=4 and b=-2, which is answer A.


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