Answer:
4. 2(x+5)
Step-by-step explanation:
[tex]\displaystyle\frac{\left(\frac{x^2-25}{14}\right)}{\left(\frac{x-5}{28}\right)}=\dfrac{(x+5)(x-5)}{14}\cdot\dfrac{28}{(x-5)}\\\\=2(x+5)[/tex]
Of course, 28 = 2·14 and like factors in the numerator and denominator cancel.
