mecca99
mecca99 mecca99
  • 09-04-2016
  • Mathematics
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f(x)= 3/2 x+b

in the function above, b is a constant. if f(6)=7, what is the value of f(-2)?

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Аноним Аноним
  • 09-04-2016
f(x)=3/2 x+b
1)we have to calculate b
f(6)=7   ⇒  3/2 (6)+b=7
9+b=7
b=7-9
b=-2

Then: f(x)=3/2  x - 2

2) Now, we calculate f(-2):
f(-2)=3/2 (-2) - 2=-3-2=-5

Answer:  f(-2)=-5

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