Answer:
[tex]x=2-\sqrt{3}[/tex]
Step-by-step explanation:
we are given one of root as
[tex]x=2+\sqrt{3}[/tex]
since, this is a root of polynomial
and this sqrt roots
we know that
sqrt roots and complex roots of any polynomial always exists in conjugate form
For example:
if we have root as
[tex]x=a+\sqrt{b}[/tex]
then other root must be conjugate of it
[tex]x=a-\sqrt{b}[/tex]
because both roots makes polynomial of real coefficient
so, other root must be
[tex]x=2-\sqrt{3}[/tex]
