Answer:
1 or -1
Step-by-step explanation:
To start, let's add in the 0x. We get [tex]x^2 + 0x - 1 = 0[/tex]. Now, we use the quadratic formula which is [tex]\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex], where a, b, and c are the coefficients in a quadratic ax^2 + bx + c, so plugging in the values, we get [tex]\frac{-0\pm\sqrt{0^2-4(1)(-1)}}{2} \implies \frac{0\pm\sqrt{0-(-4)}}{2} \implies \frac{0\pm\sqrt{4}}{2} = \frac{0\pm2}{2} \implies 1$ $ or $ $ -1. \blacksquare[/tex]
