Answer:
[tex]y(x^2+1)(x^2-5)[/tex]
Step-by-step explanation:
Factor the expression by first finding a GCF. Each term has the y variable and this can be pulled out as the GCF.
[tex]x^4y-4x^2y-5y\\y(x^4-4x^2-5)[/tex]
To further factor the expression break the polynomial into two binomials.
To factor into two binomials, find factors that multiply to -5 and add to -4.
-5 and 1 are factors and these make the binomials [tex](x^2+1)(x^2-5)[/tex].
The final factorization is [tex]y(x^2+1)(x^2-5)[/tex]
