stebux22 stebux22
  • 07-02-2019
  • Mathematics
contestada

Find the coordinate of the vertex of the following parabola algebraically. y=2x^2-28x+80

Respuesta :

jimrgrant1 jimrgrant1
  • 07-02-2019

Answer:

vertex = (7, - 18)

Step-by-step explanation:

given a parabola in standard form : ax² + bx + c : a ≠ 0

Then the x- coordinate of the vertex is

[tex]x_{vertex}[/tex] = - [tex]\frac{b}{2a}[/tex]

y = 2x² - 28x + 80 is in standard form

with a = 2, b = -28 and c = 80, hence

[tex]x_{vertex}[/tex] = - [tex]\frac{-28}{4}[/tex] = 7

substitute x = 7 into the equation for corresponding value of y

y = 2(7)² - 28(7) + 80 = 98 - 196 + 80 = - 18

vertex = (7, - 18)


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