Answer:
See below.
Step-by-step explanation:
The quadratic formula is [tex]x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}[/tex]. Here a=1, b=1, and c=-4.
Substitute and you'll have:
[tex]x=\frac{-b+/-\sqrt{b^2-4ac} }{2a} =\frac{-1+/-\sqrt{1^2-4(1)(-4)} }{2(1)}=\frac{-1+/-\sqrt{1+16} }{2)}=[/tex]
[tex]\frac{-1+/-\sqrt{17} }{2}[/tex]
