Answer:
The quotient = 2x - 1 and the remainder = 4x + 2
Step-by-step explanation:
[tex]\frac{2x^{3}+5x^{2}-7x+6}{x^{2}+3x-4}=2x+\frac{-x^{2}+x+6}{x^{2}+3x-4}[/tex]
[tex]\frac{-x^{2}+x+6 }{x^{2}+3x-4}=-1+\frac{4x+2}{x^{2}+3x-4}[/tex]
The quotient = 2x - 1 and the remainder = 4x + 2
