rapatel813
rapatel813 rapatel813
  • 08-04-2019
  • Mathematics
contestada

Find two consecutive positive integers such that the square of the first decreased by 17 equals 4 times the second.

Respuesta :

calculista
calculista calculista
  • 04-07-2019

Answer:

The two consecutive positive integers are 7 and 8

Step-by-step explanation:

Let

x ----> the first positive integer

x+1 ----> the second consecutive positive integer

we know that

[tex]x^{2} -17=4(x+1)[/tex]

Solve for x

[tex]x^{2} -17=4x+4\\ \\x^{2}-4x-21=0[/tex]

Solve the quadratic equation by graphing

The solution is x=7

see the attached figure

Find the value of x+1

x+1=7+1=8

therefore

The two consecutive positive integers are 7 and 8

Ver imagen calculista
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