Answer:
[tex](2,3)[/tex]
Step-by-step explanation:
The given equations are:
1st: -3x=42-16y
2nd: 14x=76-16y
Subtract the first equation from the second one:
14x--3x=76-42-16y--16y
14x+3x=34-16y+16y
17x=34
[tex]x=\frac{34}{17}=2[/tex]
We plug in x-value into the second equation to get:
14(2)=76-16y
14x=76-32
28-76=-16y
-48=-16y
Divide both sides by -16
y=3
