ellianna71 ellianna71
  • 07-05-2019
  • Mathematics
contestada

X^2+y^2-4x+2y-31=0 what are the center and radius of the circle? Show work

Respuesta :

Helpmeplease12389 Helpmeplease12389
  • 07-05-2019

Answer:

25y-4x

Step-by-step explanation:

Answer Link
Nevens
Nevens Nevens
  • 07-05-2019

[tex]{x}^{2} + {y}^{2} - 4x + 2y - 31 = 0 \\ {x}^{2} + {y}^{2} - 4x + 2y = 31 \\ ({x}^{2} - 4x + 4) +( {y}^{2} +2y + 1) = 31 + 4 + 1 \\ {(x - 2)}^{2} + {(y + 1)}^{2} = 36 = {6}^{2} [/tex]

so from the equation

center ( 2 , -1 )

radius 6

Answer Link

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