Answer:
Center (-13,11) , radius 3
Step-by-step explanation:
The given circle has equation
[tex]x^2+y^2+26x-22y+281=0[/tex]
We compare this to the general equation.
[tex]x^2+y^2+2ax+2by+c=0[/tex]
where (-a,-b) is the center.
This implies that;
2a=26
[tex]\Rightarrow a=13[/tex]
2b=-22
b=-11
The center is therefore (-13,11)
The radius is given by
[tex]r=\sqrt{a^2+b^2-c}[/tex]
[tex]r=\sqrt{13^2+(-11)^2-281}[/tex]
[tex]r=\sqrt{9}[/tex]
The radius is 3
