Answer:
[tex]\frac{29u}{5x}[/tex]
Step-by-step explanation:
If 'x' does not equal 0 then:
[tex]\frac{u}{x}+\frac{5u}{x}-\frac{u}{5x}[/tex] ⇒ [tex]\frac{6u}{x}-\frac{u}{5x}[/tex]
⇒ [tex]\frac{29u}{5x}[/tex]
Then, the solution is: [tex]\frac{29u}{5x}[/tex]
