Answer:
[tex]W=50J[/tex]
Explanation:
The work done [tex]W[/tex] and the energy taken [tex]Q_{in}[/tex] by a heat engine are related to the efficiency [tex]\eta[/tex] by the expression
[tex]\eta=\frac{W}{Q_{in}}[/tex]
The efficiency is [tex]\eta[/tex]=25%, the numerical form of this percentage is 0.25 and the energy taken is [tex]Q_{in}[/tex]=200J. Replacing in the formula:
[tex]0.25=\frac{W}{200}\\W=200*0.25\\W=50J[/tex]
