Answer:
12% is the mass percent of methanol in the solution.
Explanation:
Mass of water = 100.0 g
Mass of NaCl = 10.0 g
Mass of methanol = 15.0 g
Mass of the solution = 100.0 g+ 10.0 g+ 15.0 g = 125.0 g
[tex]Mass\%=\frac{\text{mass of compound}}{\text{Total mass of solution}}\times 100[/tex]
[tex]Methanol\%=\frac{15.0 g}{125.0 g}\times 100=12\%[/tex]
12% is the mass percent of methanol in the solution.
