leannewells2880 leannewells2880
  • 10-08-2019
  • Mathematics
contestada

what are the solutions to

x^2+4x+4=12

A. x=2√3+2
B. x=2√3-2
C=-√2+12
D=√2+12
E=-2√3+2
F=-2√3-2​

Respuesta :

jimrgrant1 jimrgrant1
  • 10-08-2019

Answer:

B and F

Step-by-step explanation:

Given

x² + 4x + 4 = 12 ( subtract 4 from both sides )

x² + 4x = 8

Using the method of completing the square to solve for x

add ( half the coefficient of the x- term )² to both sides

x² + 2(2)x + 4 = 8 + 4, that is

(x + 2)² = 12 ( take the square root of both sides )

x + 2 = ± [tex]\sqrt{12}[/tex] ( subtract 2 from both sides )

x = ± [tex]\sqrt{12}[/tex] - 2

  = ± 2[tex]\sqrt{3}[/tex] - 2

Hence

x = 2[tex]\sqrt{3}[/tex] - 2 → B

x = - 2[tex]\sqrt{3}[/tex] - 2 → F

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