Answer:
B. 1.09Ω
Explanation:
Parallel resistors you should add their reciprocal values and then take the reciprocal of the result:
So 2, 6 and 4 Ω become:
[tex]\frac1R = \frac12 + \frac16 + \frac14 = \frac{11}{12}[/tex]
So [tex]R = \frac{12}{11}[/tex] ≈ 1.09
