Answer:
Step-by-step explanation:
Given that
[tex]x^2 ≡ 53 (mod 77)[/tex]
Right side has values as
53, 53+77, 53+2(77),+....
We have to find one which is a perfect square.
We have from this series 361 is 19 square
Thus [tex]x =19.[/tex]
Next is [tex]x^2=900\\x=30[/tex]
[tex]x^2=2209\\x=47[/tex] and so on.
