[tex]3+\dfrac{1}{2}(3-x)<-7\qquad\text{subtract 3 from both sides}\\\\\dfrac{1}{2}(3-x)<-10\qquad\text{multiply both sides by 2}\\\\2\!\!\!\!\diagup^1\cdot\left(\dfrac{1}{2\!\!\!\!\diagup_1}\right)(3-x)<(2)(-10)\\\\3-x<-20\qquad\text{subtract 3 from both sides}\\\\-x<-23\qquad\text{change the all signs}\\\\x>23[/tex]
