Answer:
Option e. [tex]24x^{6}y^{4}[/tex]
Step-by-step explanation:
we know that
When multiply powers of the same base, add the exponents together
we have
[tex](4x^{2} y)(2x^{3}y)(3xy^{2})[/tex]
Group terms that contain the same variable
[tex](4*2*3)(x^{2}*x^{3}*x)(y*y*y^{2})[/tex]
[tex](24)(x^{2+3+1})(y^{2+1+1})[/tex]
[tex](24)(x^{6})(y^{4})[/tex]
[tex]24x^{6}y^{4}[/tex]
