Answer:
\frac{13+\left(-3\right)^2+4\left(-3\right)+1-\left[-10-\left(-6\right)\right]}{\left[4+5\right]\div \left[4^2\:−\:3^2\left(4−3\right)−8\right]+12}
Step-by-step explanation:
\frac{13+\left(-3\right)^2+4\left(-3\right)+1-\left(-10-\left(-6\right)\right)}{\frac{4+5}{\left(4^2-3^2\left(4-3\right)-8\right)+12}}
