Answer:
So after 1.0301 sec we hear the splash
Explanation:
We have given that height of the well h = 5.2 m
As the stone is dropped from rest so initial velocity u = 0 m/sec
Acceleration due to gravity [tex]g=9.8m/sec^2[/tex]
We have to find the time
From second equation of motion we know that
[tex]h=ut+\frac{1}{2}gt^2[/tex]
[tex]5.2=0\times t+\frac{1}{2}\times 9.8\times t^2[/tex]
[tex]t^2=1.061[/tex]
t = 1.0301 sec
